Question

What is the sum of all positive two digit number is

Answer 1

Answer:

The sum of two positive integers is always positive.

Let the digit at the tens place be x and the digit at the unit place be y. Required Number = (10x+y). Number obtained on reversing the digits = (10y+x). Hence, the required number is 57.

Step-by-step explanation:

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Answer 2

Answer:

4950

Step-by-step explanation:

t1= 1 , tn=99, d =1

sn = n/2 (2a+(n-1)d)

s99=99/2(2(1)+ 98×1)

4950

hope it helps you