What is the sum of all the digits in all the numbers from 1 to 1000?
Answers
Answered by
10
Answer:
500,500
Step-by-step explanation:
Let's look at some patterns:
1 + 1000 = 1001
2 + 999 = 1001
3 + 998 = 1001
4 + 997 = 1001
.
.
.
So there are 500 pairs of numbers that have a sum of 1001.
Thus, the sum of numbers from 1 to 1000 is 500*1001 = 500,500.
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Answered by
5
Formula
Sn = n/2(a+n)
=1000/2(1 + 1000)
= 500 * 1001
= 500,500
Sn = n/2(a+n)
=1000/2(1 + 1000)
= 500 * 1001
= 500,500
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