What is the sum of all the interior angles (marked in the figure) of polygon PQRSTUV
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€‹pls answer Q 5 What is the sum of all the interior angles (marked in the figure) of polygon PQRSTUV? A 360 ° B 420 ° C 720 ° D 900 °
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The adjoining star contains a regular pentagon.
So, sum of interior angles = (5-2) x
180 = 540°
In regular polygon, each angle is of same
measure
Each interior angle measures 108°
It's supplementary angle measures 180 108° = 720
Now the triangles formed by the star are isosceles, so the othere angle at the base
measures 720
measure of an angle at the vertex will be
180° 72° - 72°= 36°
Each angle at the vertices of star has a
measure of 36°.
Thus, the sum of all the angle at five vertices of the star =5 x 36° = 180°
Hence, the answer is 180°.
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