Question

what is the sum of each interior angle in a (Quadrilateral) whose measures are 96 degree,84 degree, 2x and x ?

Answer 1

Given

⇒∠A=96° , ∠B = 84° ,∠C= 2x and ∠D=x

To Find

⇒The value of x

Now

The sum of all interior angle in quadrilateral is 360°

⇒∠A + ∠B + ∠C + ∠D = 360°

⇒96° + 84° + 2x + x = 360

⇒180° + 3x° = 360°

⇒3x = 360° - 180°

⇒3x = 180

⇒x = 180/3

⇒x = 60°

Now we get

⇒∠A=96° , ∠B = 84° ,∠C= 2×60° = 120 and ∠D=60°

Now check our Answer

⇒∠A + ∠B + ∠C + ∠D = 360°

⇒96° + 84° + 120° + 60° = 360°

⇒180° + 180° = 360°

⇒360° = 360°

LHS = RHS

Answer 2

Answer:

Given :-

Angles of Quardilateral are 96⁰,84⁰,2x and x

To Find :-

x

Solution :-

We know that sum of all angles in a Quadrilateral is 360⁰.

96 + 84 + 2x + x = 360

180 + 3x = 360

3x = 360 - 180

3x = 180x = 180/3

x = 60⁰

2x = 60 × 2 = 120⁰