Question

what is the sum of first 11 terms of an A.P. whose middle term is 30
please answer my question​

Answer 1

Answer:

Let the numbers be (a−5d),(a−4d),(a−3d),(a−2d),(a−d),a,(a+d),(a+2d),(a+3d),(a+4d),(a+5d).Then,

Middle Term=6th term=a=30.

Now, Sum=(a−5d)+(a−4d)+(a−3d)+(a−2d)+(a−d)+a+(a+d)+(a+2d)+(a+3d)+(a+4d)+(a+5d)=11a

∴Sum=11×30=330