Question

what is the sum of first 110 consecutive natural numbers?
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Answer 1

Answer:

The number series 1, 2, 3, 4, . . . . , 109, 110.

The first term a = 1

The common difference d = 1

Total number of terms n = 110

step 2 apply the input parameter values in the formula

Sum = n/2 x (a + Tn)

= 110/2 x (1 + 110)

= 12210/2

1 + 2 + 3 + 4 + . . . . + 109 + 110 = 6105

Therefore, 6105 is the sum of positive integers upto 110.