Question

What is the sum of first five positive integers divisible by 6

Answer 1

6,12,..
here a=6. d=6. n=5
s=5/2{2×6+(5-1)6}
=5/2(12+24)
=5/2×36
=5×18
=90

Answer 2

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Here is your answer

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The no. of list which is divisible by 6 ..are

6 , 12 , 18 , 24, and 30


Use the formula of Sum of Term of AP

Sn = n/2[a + l ]


n = 5 , a = 6 and l ( last term) = 30


$\frac{n}{2} (a + l) \\ \\ \frac{5}{2}(6 + 30 ) \\ \\ \frac{5}{2} \times 36 \\ \\ 5 \times 18 \\ \\ 90$

There the sum of 5 positive integer which are divisible by 6 is 90 ..


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