what is the sum of first n terms of an AP is(3n²+5n), Which term of this AP is 152
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25th term.
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Given:
The sum of the first "n" terms of AP is (3n² + 5n)
To find:
In which AP term 152 contain.
Solution:
The given term (3n² + 5n)
Substitute "n=1" in given term
S₁ = a₁
⇒ 3 + 5 = 8
Substitute "n=2" in given term
S₂ = a₁ + a₂
⇒ 12 + 10 = 22
a₂ = S₂ - S₁
⇒ 22 - 8 = 16
S₃ = a₁ + a₂ +a₃
⇒ 27 + 15
= 42
a₃ = S₃ - S₂
⇒ 42 - 22 = 20
Given AP is,
8,14,20...
a = 8
d = 6
Tm = 152
152 = (8 + (n-1)6)
152 = (8+ 6n - 6)
152 = 2 + 6n
152 - 2 = 6n
150 = 6n
= n
∴ n = 25.
The AP of 152 is 25th term.
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