Question

what is the sum of first n terms of the Ap a,3a .5a.....
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Answer 1

Answer:

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sum of AP = $\frac{n}{2}$(2a + (n - 1) d)

d = 2a and a = a and n = n

sum of AP = $\frac{n}{2}$(2a + (n - 1) 2a)

by taking 2a common

sum of AP = $\frac{n}{2}$ × 2a(1 + (n - 1) )

sum of AP = ${n}a( n )$

sum of AP = $a{n}^2$

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