Question

What is the sum of first ten multiples of 6

Answer 1

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6+12+18+24+30+36+42+48+54+60 = 330

Answer 2

AP=6,12,18,24.......

a=6

d=12-6=6

n=10

Sn=n/2[2a +(n-1)d]

Sn=10/2[2*6+9*6]

Sn=5[12+54]

Sn=5*66

Sn=330

Therefore sum of first 10 multiples of 6 is 330