What is the sum of largest three digit positive integer and the smallest two digit negative integer
Answers
Answered by
8
largest three digit positive integer is 999
smallest two digit negative integer is -99
Sum = 999 + (-99)
=999-99
=900
smallest two digit negative integer is -99
Sum = 999 + (-99)
=999-99
=900
Diksha123:
ur ans is rong
as smallest digit is 10
not 99
In negative numbers,-10 is greater than -99.so the smallest 2 digit in negative numbers is -99
Similar questions