What is the sum of multiple of 3 between 3 to 232.
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Hii friend,
The numbers between 3 to 232 which is divisible by 3 are = 3,6,9,12,.....231
AP = 3,6,9,12........,231
Here,
First term ( A) = 3
Common difference (D) = 3
Last term ( Tn ) = 231
A+(N-1) × D = 231
3 + (N-1) × 3 = 231
3 + 3N - 3 = 231
3N = 231
N = 231/3
N = 77
Therefore,
77 terms are divisible by 3 between 3 to 232
Sn = N/2 [ 2A +(N-1) × D]
= 77/2 [ 2 × 3 + ( 77-1) × 3 ]
= 77/2 [ 6 + 228]
= 77/2 × 234
= 77 × 117 = 9009
Therefore,
The sum of NUMBERS between 3 to 232 which is divisible by 3 is 9009.
HOPE IT HELPS!!!!
The numbers between 3 to 232 which is divisible by 3 are = 3,6,9,12,.....231
AP = 3,6,9,12........,231
Here,
First term ( A) = 3
Common difference (D) = 3
Last term ( Tn ) = 231
A+(N-1) × D = 231
3 + (N-1) × 3 = 231
3 + 3N - 3 = 231
3N = 231
N = 231/3
N = 77
Therefore,
77 terms are divisible by 3 between 3 to 232
Sn = N/2 [ 2A +(N-1) × D]
= 77/2 [ 2 × 3 + ( 77-1) × 3 ]
= 77/2 [ 6 + 228]
= 77/2 × 234
= 77 × 117 = 9009
Therefore,
The sum of NUMBERS between 3 to 232 which is divisible by 3 is 9009.
HOPE IT HELPS!!!!
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