Question

What is the sum of multiple of 3 between 3 to 232.

Answer 1

Hii friend,

The numbers between 3 to 232 which is divisible by 3 are = 3,6,9,12,.....231

AP = 3,6,9,12........,231

Here,

First term ( A) = 3

Common difference (D) = 3

Last term ( Tn ) = 231

A+(N-1) × D = 231

3 + (N-1) × 3 = 231

3 + 3N - 3 = 231

3N = 231

N = 231/3

N = 77

Therefore,

77 terms are divisible by 3 between 3 to 232

Sn = N/2 [ 2A +(N-1) × D]

= 77/2 [ 2 × 3 + ( 77-1) × 3 ]

= 77/2 [ 6 + 228]

= 77/2 × 234

= 77 × 117 = 9009

Therefore,

The sum of NUMBERS between 3 to 232 which is divisible by 3 is 9009.

HOPE IT HELPS!!!!