What is the sum of n natural numbers between 1 and 150 which is multiple of 3?
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Answer:
3825
Step-by-step explanation:
The numbers are 3, 6, 9…., 150
Nth term of an AP = a + (n - 1)d
3 + (n - 1)3 = 150 ⇒ n = 50
Sum of n terms of an AP = n/2(2a + (n - 1)d)
Where a is first term, n is number of terms and d is common difference
a = 3, n = 50 and d = 3
Sum = 50/2 × (6 + 49 × 3) = 3825
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