Question

What is the sum of ‘n’ terms in the series?
A) log[n(n−1)/m(n+1)]n/2
B) log[mm/nn]n/2
C) log[m(1−n)/n(1−m)]n/2
D) log[m(n+1)/n(n−1)]n/2

Answer 1

I dont know the answer

if any body knows the answer pls tell me