Question

what is the sum of n terms of gp and ap?​

Answer 1

Explanation:

$\huge\blue{HELLO\:MATE}$

IN AN AP

LET a BE THE 1ST TERM

d BE THE COMMON DIFFERENCE

AND

n BE THE NO. OF TERMS

THEN SUM OF N TERMS (Sn)=n/2[2a+(n-1)d]

IN A GP

LET a BE THE 1ST TERM

r BE THE CONSTANT RATIO

AND

n BE THE NO. OF TERMS

THEN SUM OF N TERMS (Sn)=

$a \dfrac{( {r}^{n} - 1) }{(r - 1)}$

Answer 2

Answer:

The general form of an Arithmetic Progression is a, a + d, a + 2d, a + 3d and so on. Thus nth term of an AP series is Tn = a + (n - 1) d, where Tn = nth term and a = first term. Here d = common difference = Tn - Tn-1. The sum of n terms is also equal to the formula where l is the last term.