what is the sum of n terms of the series
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a=root 2
d= 2root2- root 2=root 2
hence d=root 2
Sn=n/2(2a+(n-1)d)
=n/2(2 root2+n root 2-root 2)
=n/2( root2(1+n))
on solving
=n(n+1)/root2
hence option (c) is correct
d= 2root2- root 2=root 2
hence d=root 2
Sn=n/2(2a+(n-1)d)
=n/2(2 root2+n root 2-root 2)
=n/2( root2(1+n))
on solving
=n(n+1)/root2
hence option (c) is correct
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