Question

What is the sum of oxidation no of various atoms in bisulfate ion (hso4-?

Answer 1

Explanation:

HEY MATE

HERE IS YOUR ANSWER

AS HYDROGEN CONTAIN+1 CHARGE

OXYGEN CONTAIN -2 CHARGE

SO HSO4-

+1+X+(4×-2)=-1 AS ANION

X=+6

BUT IN QUESTION SUM OF OXIDATION STATE WERE ASKED

H+S+4O+CHARGE ON COMPOUND

+1+6+4×-2+(-1)

AS WHOLE COMPOUND IS ELECTRICALLY NEUTRAL

ALSO ATOM WISE

H=+1

O=-8

S=+6

HOPE HELP YOU

THANKS

Answer 2

Answer:6+1-2=5

Explanation: oxidation no of :

O =-2

S=+6

H=+1

Therefore sum =5