what is the sum of squares of first 5 natural number?
Answers
Answered by
0
Answer:
the sum of the squares of first n natural
numbers = n(n+1)(2n+1)6.
Step-by-step explanation:
Answer. ⇒ n3 = 3S - 3 ∙ n(n+1)2 + n. Therefore, S = n(n+1)(2n+1)6. numbers = n(n+1)(2n+1)6.
Answered by
3
Answer:
sum of frist five natural number is 15
Step-by-step explanation:
1+2=3
3+3=6
6+4=10
10+5=15
Hope it will help you
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