Math, asked by tanijuglani480, 12 hours ago

What is the sum of terms 100 of an Arithmetic progression 4,12,20

Answers

Answered by popatkhot1977
0

Answer:

4000

Step-by-step explanation:

Arithmatic progression

4, 12 , 20....

Here a = 4 , d = 12-4 = 8 , n = 100

sn = n / 2 [ 2a + ( n-1 ) d ]

= 100 / 2 [ 2× 4 + ( 100 - 1) 8]

= 50 [ 8 + 99 × 8]

= 50 [ 8 + 792 ]

= 50 × 800

= 4000

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