What is the sum of terms 100 of an Arithmetic progression 4,12,20
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Answer:
4000
Step-by-step explanation:
Arithmatic progression
4, 12 , 20....
Here a = 4 , d = 12-4 = 8 , n = 100
sn = n / 2 [ 2a + ( n-1 ) d ]
= 100 / 2 [ 2× 4 + ( 100 - 1) 8]
= 50 [ 8 + 99 × 8]
= 50 [ 8 + 792 ]
= 50 × 800
= 4000
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