Question

what is the sum of the all 2 digit even number​

Answer 1

Answer:

∴ sum of all two digit odd positive numbers = 2475.

Answer 2

Answer:

2430is the required sum of the all 2 digit even number .

Step-by-step explanation:

Explanation:

There are total 45number of  two digit  even number .

10 , 12 , 14 , 16 .............98 .

Sum of n term of A.P = $\frac{n}{2} (2a + (n-1)d)$

Where a is first term , d is common difference .

Step 1:

We have , a = 10 ,n = 45

d = 12-10= 2

On putting the value of a , d and n in the  formula we get ,

$S_{45}$ = $\frac{45}{2} (2(10) + (45-1)2)$

⇒$S _{45}$ = $\frac{45}{2} [20 + 88]$ = $\frac{45}{2}[108]$

⇒$S_{45} = 45 (54)$ = 2430.

Final answer :

Hence , the sum of the all 2 digit even number is 2430

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