what is the sum of the angles of a 62 sided polygon ?
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When we start with a polygon with four or more than four sides, we need to draw all the possible diagonals from one vertex. The polygon then is broken into several non-overlapping triangles. The angle sum of this polygon for interior angles can be determined on multiplying the number of triangles by 180°
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Sum of interior angels = (n-2) *180
Where n is the number of sides of the given polygon.
Here, n is 62 .
So, (62-2) *180
60*180
10800°
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