what is the sum of the areas of squares of side 1cm,2cm,3cm,...10cm?
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Answered by
12
Area of square =s²
Area of given squares =(1)²+(2)²......
=1+4+9+16+25+36+49+64+81+100
=385cm²
Area of given squares =(1)²+(2)²......
=1+4+9+16+25+36+49+64+81+100
=385cm²
sailulali734:
wrong answer
Answered by
4
Area of a square = S*S = s^2
Therefore, area of a square of side -
1cm = 1^2 = 1cm^2
2cm = 2^2 = 4cm^2
3cm = 3^2 = 9cm^2
4cm = 4^2 = 16cm^2
5cm = 5^2 = 25cm^2
6cm = 6^2 = 36cm^2
7cm = 7^2 = 49cm^2
8cm = 8^2 = 64cm^2
9cm = 9^2 = 81cm^2
10cm = 10^2 = 100cm^2
Now sum of all of the above areas = 1 + 4 + 9 + 16 + 25 + 36 + 49 + 64 + 81 + 100
= 385cm^2
Hope it helps :)
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