what is the sum of the cubes of first n-natural numbers?
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sum of the first n cubes, 13+23+...+ n 3 = ( n ( n +1)/2)2, which is the square of the n th natural number.
means 36
sum of the first n cubes, 13+23+...+ n 3 = ( n ( n +1)/2)2, which is the square of the n th natural number.
means 36
mohit75759:
how to do this?
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★★★hey friend!!!!!!★★★
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⇒ the sum of the first three (n=3) cubes, it would be (1)3+23+33 or 1+8+27=36.
_____________________________________________________________
★★★hope this may help u!!!★★★
_____________________________________________________________
⇒ the sum of the first three (n=3) cubes, it would be (1)3+23+33 or 1+8+27=36.
_____________________________________________________________
★★★hope this may help u!!!★★★
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