Question

What is the sum of the digits of the number A if given 94 nines×94 fours=A?

Answer 1

Let the digit at tens place be x

Units  Place = 2x

Original number = 10(x) + 2x = 12x

Interchanged number = 10(2x) + x = 21x

21x - 12x = 18

9x = 18

x = 2

Original number = 10*2 + 2*2 = 24