What is the sum of the digits of the smallest number which remainder 2 upon being divided by 10 15 25
Answers
Answer:
The smallest number which can be divided by 10, 15, 25 = LCM(10, 15, 25) = 150
Remainder = 2
Dividend = 150 + 2 = 152
Sum of digits = 1 + 5 + 2 = 8
Step-by-step explanation:
The sum of the digits is 8.
Given data:
The sum of the digits of smaller number which remainder is 2 upon being divided by 10 25 25.
Hence to find the smallest number,
The smallest number which can be divided by 10, 15, 25 is Least Common Multiple (L.C.M)
Hence L.C.M for the 10, 15, 25 = 150
Now, we want remainder 2
Remainder = 2
Number = 150 + 2 = 152
Hence 152 is the smallest number which has remainder 2 upon being divided by 10 15 25 is 152
Now we have to find the sum of the digits of 152
Find the smallest number which leaves remainder 8 and 12 when divided by 28 and 32
(Along the answer plz tell the steps to solve this question)Sum of digits = 1 + 5 + 2 = 8
https://brainly.in/question/1196144
Hence the sum of the digits is 8
To learn more..
1) What is the smallest 4 digit number which which when divided by 16 and 18 leaves remainder 8 in each case
https://brainly.in/question/3902429
2) Find the smallest number which leaves remainder 8 and 12 when divided by 28 and 32
https://brainly.in/question/1196144