Question

What is the sum of the eleventh to twentieth terms (inclusive)of the arithmetic sequence. 7, 12, 17, 22, ... ? hence the sum of the 11th term to the 20th term is 795 WITH SOLUTIONS

Answer 1

Answer:

the sum of the 11th term to the 20th term is 795.

Answer 2

Answer:

795

Step-by-step explanation:

first find the common difference

d= 12-7=5

first term =7

so 11th term= 7+(11-1)*5 =57

20th term= 7+19*5 =102

now we have to find the sum of AP whose

first term=57 last term=102 and no of terms = 10

S= n( a+l)/2

= 10* (57+102)/2

=795