Question

What is the sum of the even integers
between 101 and 1001?​

Answer 1

Answer:

The series is given as,

102,104,..........,1000

a=102

d=104−102=2

an=a+(n−1)d

1000=102+(n−1)2

898=2(n−1)

449=n−1

n=450

Sn=n/2[2a+(n-1)d]

S450=450/2[2(102)+(450-1)2]

S450=225[204+(449)2]

S450=225(204+898)

S450=225(1102)

S450=247950

Step-by-step explanation:

Answer=247950.

Hope this helps you.