Question

what is the sum of the first 10 natural minbers ? (a)55 (b)20 (c)65 (d)11​

Answer 1

Step-by-step explanation:

option a)55 is correct..

Answer 2

$\huge\mathfrak{Answer:}$

55

$\huge\mathfrak{Solution:}$

➡️Consider the sum of first 10 natural numbers as a A.P as the first term (a) being 1 and common difference(d) being 1.

➡️GIVEN :-

N = 10

A = 1

D = 1

➡️then the sum of first 10 natural number is :-

➡️Sn = n/2 { 2a + (n - 1)d}

➡️S10= 10/2 { 2(1) + ( 10-1 ) 1 }

➡️5 ( 2+9)

➡️ 5 ( 11 )

➡️55