Question

What is the sum of the first 10 positive integers?

Answer 1

a=1,n=10,d=1

sum= 10/2(2+9×1)

5×11

=55

Answer 2

The sum of the first 10 positive integers is 55.

Step-by-step explanation:

To find : What is the sum of the first 10 positive integers?

Solution :

The 10 positive integers are 1,2,3,4...,10 which form an A.P.

Where, first term is a=1

Common difference is d=1

n=10 and l=10

The sum formula is $S_n=\frac{n}{2}[a+l]$

Substitute the values,

$S_{10}=\frac{10}{2}[1+10]$

$S_{10}=5[11]$

$S_{10}=55$

The sum of the first 10 positive integers is 55.

#Learn more

For any positive integer n the sum of the first n positive integers equals n(n+1)/2. what is the sum of all the even integers between 99 - 301? a) 10 100 b) 20 200

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