What is the sum of the first 10 terms of the sum 1, 6, 11, 16, 21?
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Answered by
0
Answer:
235
Step-by-step explanation:
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Answered by
1
Answer:
235
Step-by-step explanation:
the given AP 1, 6, 11, 16, 21 .....
a = 1
d =
a2 - a1 = a3 - a2
6 - 1 = 11 - 6
5 = 5
d = 5
Sn = n/2 [2a + (n-1)d]
S10 = 10/2 [2(1) + (10 - 1)(5)]
= 5 [2 + 9(5)]
= 5 [2 + 45]
= 5 × 47
= 235
sum of first 10 terms of AP 1, 6, 11, 16, 21 .... is 235
hope you get your answer
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