What is the sum of the first 13 terms of an arithmetic progression if the first term is -10 and last term is 26?
A) 104 B) 140 C) 84 D) 98
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Answer:A)104
Step-by-step explanation:sn=n/2(a+x_n)
sn=13/2(-10+26)
=13/2(16)
=13×8
=104
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