what is the sum of the first 20 term of an A. P., if a=4 and t20=36
a) 40
b) 200
c) 400
d) 800
Answers
Answer:
We know that the general term of an arithmetic progression with first term a and common difference d is T
n
=a+(n−1)d
It is given that the 3rd term of the arithmetic series is 7 that is T
3
=7 and therefore,
T
3
=a+(3−1)d
⇒7=a+2d....(1)
Also it is given that the 7th term is 2 more than three times its 3rd term that is
T
7
=(3×T
3
)+2=(3×7)+2=21+2=23
Thus,
T
7
=a+(7−1)d
⇒23=a+6d....(2)
Subtract equation 1 from equation 2:
(a−a)+(6d−2d)=23−7
⇒4d=16
⇒d=
4
16
⇒d=4
Substitute the value of d in equation 1:
a+(2×4)=7
⇒a+8=7
⇒a=7−8=−1
We also know that the sum of an arithmetic series with first term a and common difference d is S
n
=
2
n
[2a+(n−1)d]
Now to find the sum of first 20 terms, substitute n=20,a=−1 and d=4 in S
n
=
2
n
[2a+(n−1)d] as follows:
S
20
=
2
20
[(2×−1)+(20−1)4]=10[−2+(19×4)]=10(−2+76)=10×74=740
Hence, the sum of first 20 terms is 740.
Answer:
400
Step-by-step explanation:
t20=36
s=a+(n-1)d
36=4+(20-1)d
36-4=(19)d
32=19d
32/19=d
s20=20/2(8+19×32/19)
=10(8+32)
=10(40)
=400