Math, asked by reshmarsharief, 9 months ago

What is the sum of the first 30 terms of an AP whose nth term
is given by 9 - 4n?​

Answers

Answered by nityashree26
1

Answer:An=9-4n

if n=1 ,then A1=5

if n=2,thenA2=1

So d=A2-A1=-4

S30=n/2[2a+(n-1)d]

=30/2[2 x 5 +(30-1)-4]

=15[10+(-116)]

=15 x (-106)

=1590

Step-by-step exlanation:

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