what is the sum of the first 7 terms of the sequence of 1/7, 2/7 ,3/7
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Step-by-step explanation:
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Answer: Sum of the first 7 terms = 4
Step-by-step explanation:
The AP is 1/7, 2/7, 3/7............
common difference = t_{2} - t_{1}t2−t1
= 2/7 - 1/7
= 1/7
Therefore, a= 1/7, d= 1/7
Using sum of 'n' terms formula,
S_{n} = n/2 [2a + (n-1)d]Sn=n/2[2a+(n−1)d]
S_{7}S7 = 7/2 [2*1/7 + (7-1)* 1/7]
S_{7}S7 = 7/2 [2/7 + (6)* 1/7]
S_{7}S7 = 7/2 [2/7 + 6/7]
S_{7}S7 = 7/2 [8/7]
S_{7}S7 = 56/14
S_{7}S7 = 4
Therefore sum of the first 7 terms of the sequence is 4
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