What is the sum of the first 'n' natural number?
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First n natural numbers are in ap.
so , a will be 1
d will be 1
then sum of first n natural no. =
Sn = n/2(2a+(n-1)d)
= n/2(2(1)+(n-1)1)
=n/2(2+n-1)
=n/2(n+1)
=n²+n/2
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