What is the sum of the greatest and smallest six-digit number formed by using each of the digits 7, 4 and 0 at least once ?
Answers
Answer:
1174877
Step-by-step explanation:
So there are 6 digits available in total, and the three digits 7, 4, and 0 all have to be used at least once. Divide 6 by 3, and we get 2. This means each digit has to be used 2 times. So we have to find the greatest and smallest number we can make out of a combination of the digits 7, 4, 0, 7, 4, and 0.
If the question is asking for the greatest number, you should always start with the biggest digit you have, and basically arrange all the digits in order of size, big to small. In this case, we have 7, 7, 4, 4, 0, and 0. The correct order would be 774400. That's our first number.
If the question is asking for the smallest number, you should start with the smallest digit you have, and work your way up to the biggest digit. However, in this case, the smallest digit is 0, which cannot be the first digit of a number (given that the number isn't a decimal, which, in this case, it isn't). This means you'll have to start with the second smallest digit, which is 4, and place your 0 after 4. The point is, try to place your smallest digit at the front when it's possible, but when it's not, just use the second smallest to take its place, and continue as you would after that. So the smallest number we could form out of the given digits would be 400477.
Now all that's left to do is to add them together. 774400+400477=1174877
And that's the answer.
Ps: I did my best, hope it helps! :)