Question

what is the sum of the interior angles of a polygon having a) 5 sides b) 8 slide

Answer 1

Solution:-
Interior angle of polygon =180(n-2)
Where n is equal to sides.
So,
1)5 sides:-
$= > 180(n - 2) \\ = > 180(5 - 2) \\ = > 180 \times 3 \\ = > 540$
Hence,
Interior angle of polygon having 5 sides is 540°


2)8 sides:-
$= > 180(n - 2) \\ = > 180(8 - 2) \\ = > 180 \times 6 \\ = > 1080$
Hence,
Interior angle of polygon having 8 sides is 1080°

We can also find the interior angle by using formula
=> (2n-4)right angle
=>(2n-4)×90°