what is the sum of the measures of the angles of a convex quadrilateral? will this property hold is a quadrilateral is not convex (make a non -convex quadrilateral and try)
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The convex quadrilateral has all the angles less than 180 or equal to 180
The concave quadrilateral has all the angles greater than 180
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Let ABCD be a convex quadrilateral....
From the figure, we infer that the quadrilateral ABCD is formed by two triangles,
that is: ∆ADC & ∆ABC
Since, we know that sum of the interior angle of triangle is 180°, the sum of the measures of the angles is 180°+180°=360°.
Let us take another quadrilateral ABCD, which is not a convex.
Join BC, such that it divides ABCD into two triangles ∆ABC & ∆BCD.
In ∆ABC,
<1+<2+<3=180° (Angle sum property of triangle)
In ∆BCD,
<4+<5+<6=180° ( Angle sum property of triangle)
➤ <1+<2+<3+<4+<5+<6=180°+180°
➤<1+<2+<3+<4+<5+<6=360°
➤<A+<B+<C+<D+=360°
✰Thus, this property hold if the quadrilateral is not convex.