what is the sum of the numbers from 1 to 2018?
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1+2+3+........+ 2018
this is an arithmetic sequence with
a= 1
d=1
n=2018
sum of n terms =(n/2)[2a+(n-1)d]
sum of 2018 terms=
(2018/2)[2+(2017×1)]
= 1009×2019
=2037171
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