what is the sum of the sizes of the interior angles of a polygon with 53 sides
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Answered by
9
Answer:
Step-by-step explanation:
Sum of interior angle of a polygen =(n-1)× 90°
Where n is the number of side
Sum of interior angle of a polygen with 53 sides =(53-1)×90°
= 52×90° =4680°
Answered by
4
Answer:
9180°
Step-by-step explanation:
the formula is (n-2) ×180 degrees
so n is 53
(53-2) × 180
51×180 which is 9180degrees
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