Question

what is the sum of the smallest two digit negative integer that is multiplyed by 6 and largest two digit positive integer that is multiplyed by 4.

please answer fast
urgent​

Answer 1

Answer:

Smallest two digit number negative that is multiplied by 6 = -60

Largest two digit positive integer multiplied by 4 =99*4= 396

Sum= 396-60

=336

Answer 2

Answer:

336

Step-by-step explanation:

smallest two digit negative integer = -10

largest two digit positive number = 99

a/q,

(-10*6) + (99*4)

= -60 + 396

= 336