Question

What is the sum of the two consecutive numbers, if the difference of whose squares is 19?

a. 9

b. 10

c. 18

d. 19?

Answer 1

Answer:

10 square is 100

9 square is 81

If we subtract both squares

We get the answer as 19

So according to question we have to add both no whose squares difference is 19

:therefore 10+9=19

Answer is 19

Step-by-step explanation:

Answer 2

Answer:

Solution

Given :-

Sum of two number be = 19

Difference be both be = 9

Find :-

These Both Number

Explanation

Let,

First Number be = x

Second Number be = y

Case(1).

(Sum of two number be = 19)

==> x + y = 19 _________(1)

Case(1).

(Difference be both be = 9)

==> x - y = 9 __________(2)

Add equ(1) & equ(2)

==> 2x = 19 + 9

==> 2x = 28

==> x = 28/2

==> x = 14

Keep value of x in equ(1)

==> 14 + y = 19

==> y = 19 - 14

==> y = 5

Hence

First Number be = 14

Second Number be = 5

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