Question

what is the sum of three interiorangles and triangle​

Answer 1

sum of three interior angles of triangle is 180 degrees

Answer 2

Answer:

A triangle ABC.

Given :A triangle ABC. To prove :

Given :A triangle ABC. To prove :∠A+∠B+∠C=180

Given :A triangle ABC. To prove :∠A+∠B+∠C=180 o

Given :A triangle ABC. To prove :∠A+∠B+∠C=180 o ⟹∠1+∠2+∠3=180

Given :A triangle ABC. To prove :∠A+∠B+∠C=180 o ⟹∠1+∠2+∠3=180 o

Given :A triangle ABC. To prove :∠A+∠B+∠C=180 o ⟹∠1+∠2+∠3=180 o

Given :A triangle ABC. To prove :∠A+∠B+∠C=180 o ⟹∠1+∠2+∠3=180 o Construction :

Given :A triangle ABC. To prove :∠A+∠B+∠C=180 o ⟹∠1+∠2+∠3=180 o Construction :Through A, draw a line l parallel to BC.

Given :A triangle ABC. To prove :∠A+∠B+∠C=180 o ⟹∠1+∠2+∠3=180 o Construction :Through A, draw a line l parallel to BC. Proof :

Given :A triangle ABC. To prove :∠A+∠B+∠C=180 o ⟹∠1+∠2+∠3=180 o Construction :Through A, draw a line l parallel to BC. Proof :Since l∥ BC. Therefore,

Given :A triangle ABC. To prove :∠A+∠B+∠C=180 o ⟹∠1+∠2+∠3=180 o Construction :Through A, draw a line l parallel to BC. Proof :Since l∥ BC. Therefore,∠2=∠4 …eq(i)

Given :A triangle ABC. To prove :∠A+∠B+∠C=180 o ⟹∠1+∠2+∠3=180 o Construction :Through A, draw a line l parallel to BC. Proof :Since l∥ BC. Therefore,∠2=∠4 ...eq(i)And, ∠3=∠5...eq(ii)

Given :A triangle ABC. To prove :∠A+∠B+∠C=180 o ⟹∠1+∠2+∠3=180 o Construction :Through A, draw a line l parallel to BC. Proof :Since l∥ BC. Therefore,∠2=∠4 ...eq(i)And, ∠3=∠5...eq(ii)adding eq(i)and(ii)

Given :A triangle ABC. To prove :∠A+∠B+∠C=180 o ⟹∠1+∠2+∠3=180 o Construction :Through A, draw a line l parallel to BC. Proof :Since l∥ BC. Therefore,∠2=∠4.. eq(i)And, ∠3=∠5..eq(ii)adding eq(i)and(ii)Therefore, ∠2+∠3=∠4+∠5

Given :A triangle ABC. To prove :∠A+∠B+∠C=180 o ⟹∠1+∠2+∠3=180 o Construction :Through A, draw a line l parallel to BC. Proof :Since l∥ BC. Therefore,∠2=∠4 ...eq(i)And, ∠3=∠5...eq(ii)adding eq(i)and(ii)Therefore, ∠2+∠3=∠4+∠5∠1+∠2+∠3=∠1+∠4+∠5 [adding∠1bothSide]

Given :A triangle ABC. To prove :∠A+∠B+∠C=180 o ⟹∠1+∠2+∠3=180 o Construction :Through A, draw a line l parallel to BC. Proof :Since l∥ BC. Therefore,∠2=∠4 ...eq(i)And, ∠3=∠5...eq(ii)adding eq(i)and(ii)Therefore, ∠2+∠3=∠4+∠5∠1+∠2+∠3=∠1+∠4+∠5 [adding∠1bothSide]∠1+∠2+∠3=180°

Thus, the sum of three angles of a triangle is 180 °.

Step-by-step explanation:

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