What is the sum of two consecutive even numbers, the difference of whose squares is 84?
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Let’s assume the required numbers to be x and x + 2.
Then, (x + 2)² - x² = 84
This is, x² +2x + 2x +4 - x² (both the x² get cancelled being negative and positive numbers)
Therefore 4x + 4 = 84
Thus, 4x = 80 x = 20.
The required sum is = x + (x + 2) = 2x + 2 = 42.
Then, (x + 2)² - x² = 84
This is, x² +2x + 2x +4 - x² (both the x² get cancelled being negative and positive numbers)
Therefore 4x + 4 = 84
Thus, 4x = 80 x = 20.
The required sum is = x + (x + 2) = 2x + 2 = 42.
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Required sum is 2x+2=42
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