What is the sum of two consecutive numbers the difference of whose square is 19?
Answers
Answered by
4
Hi Mate !!
Let the 1st no. be x
It is given that the nos.are consecutive then the other no. is x + 1
• Difference of Square is 19
( x + 1 )² - x² = 19
[ Using identity ( a + b )² = a² + 2ab + b² ]
x² + 2x + 1 - x² = 19
2x = 19 - 1
2x = 18
x = 9
So, the 1st no.is ( x ) :- 9
2nd no. is ( x + 1 ) :- 10
• Sum of two consecutive no. is :-
9 + 10 = 19 !!
Let the 1st no. be x
It is given that the nos.are consecutive then the other no. is x + 1
• Difference of Square is 19
( x + 1 )² - x² = 19
[ Using identity ( a + b )² = a² + 2ab + b² ]
x² + 2x + 1 - x² = 19
2x = 19 - 1
2x = 18
x = 9
So, the 1st no.is ( x ) :- 9
2nd no. is ( x + 1 ) :- 10
• Sum of two consecutive no. is :-
9 + 10 = 19 !!
Answered by
0
19 is the answer.....
Similar questions