Question

What is the sum of two consecutive numbers whose squares is 19?

Answer 1

Answer:

±6.08

Step-by-step explanation:

Let the consecutive numbers be x and x+1

x² + (x+1)² = 19

x² + x² + 2x + 1 = 19

2x² + 2x - 18 = 0

x² + x - 9 = 0  

x = -1 ±√1+36 / 2 = -1 ±√37/2

if x = -1+√37/2

      => 2.54.

if x = -1-√37/2

      => -3.54.

The sum of two consecutive numbers 2.54 and 3.54 = 2.54 + 3.54 = 6.08

The sum of two consecutive numbers -3.54 and -2.54 = -2.54 - 3.54 = -6.08