Question

. What is the sum of two numbers whose difference
is 45 and the quotient of the greater number by
the lesser number is 4?

Answer is 75 pls tell me the method​

Answer 1

Let the two numbers be x and y.

Given quotient is 4.

x/y = 4

x=4y

Also given difference is 45

x-y=45

4y-y=45

3y=45

y=15

So x=4y =4*15=60

So sum is 60+15=75

Answer 2

Answer:

let the two numbers be x and y such that x>y.

then, (x-y)= 45.. ........(I)

when x is divided by y , we get quotient as 4

so, x= 4y.........(2). (since the remainder is 0).

then, by putting x into EQ.(I),

: . 4y-y= 45

3y=45

so, y = 15

and x= 4y

x= (4×15)

x = 60.

thus ,sum of the numbers= (x+y)=(60+15)=75.