Question

what is the sum of X + y + z + w from the given figure ​

Answer 1

Answer:

x 100

y 60

z 100

w 80

this is the right answer

Answer 2

Given :

• Three interior angles 80° , 80° and 120°..

To Find :

• Value of x , y ,z ,w

Solution :

$\longmapsto\tt{x+80\degree=180\degree\:(Linear\:Pair)}$

$\longmapsto\tt{x=180\degree-80\degree}$

$\longmapsto\tt\bold{x=100\degree}$

Similarly ,

$\longmapsto\tt{y+120\degree=180\degree\:(Linear\:Pair)}$

$\longmapsto\tt{y=180\degree-120\degree}$

$\longmapsto\tt\bold{y=60\degree}$

Similarly ,

$\longmapsto\tt{z+80\degree=180\degree\:(Linear\:Pair)}$

$\longmapsto\tt{z=180\degree-80\degree}$

$\longmapsto\tt\bold{z=100\degree}$

Now ,

As we know that sum of exterior angle of a quardrilateral is 360° :

$\longmapsto\tt{80\degree+80\degree+120\degree+a=360\degree}$

$\longmapsto\tt{260\degree+a=360\degree}$

$\longmapsto\tt{a=360\degree-260\degree}$

$\longmapsto\tt\bold{a=100\degree}$

Now ,

$\longmapsto\tt{100\degree+w=180\degree\:(Linear\:Pair)}$

$\longmapsto\tt{w=180\degree-100\degree}$

$\longmapsto\tt\bold{w=80\degree}$

Therefore :

$\longmapsto\tt\bold{x=100\degree}$

$\longmapsto\tt\bold{y=60\degree}$

$\longmapsto\tt\bold{z=100\degree}$

$\longmapsto\tt\bold{w=80\degree}$