Question

What is the sum of zeros of polynomial 2x2-3k?

Answer 1

Answer:

Let f(x) = kx² + 2x + 3k. Here a = k, b = 2 and c = 3k. Sum of zeroes, α + β = -b/a = -(2)/k = -2/k. Product of zeroes, αβ = c/a = 3k/k = 3. Given, Sum of zeroes = Product of zeroes-2/k = 3. k = -2/3.

Answer 2

The solution has been attached to the file.

The important thing you must know: $\sf \alpha + \beta = \dfrac{- coefficient \ of\ x}{coefficient \ of \ x^2}$

Where Alpha and beta are the zeroes of the given polynomial.