What is the sum (Two-fifths x + StartFraction 5 over 8 EndFraction) + (one-fifth x minus one-fourth)?
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Given : (Two-fifths x + 5 over 8 ) + (one-fifth x minus one-fourth)
(2x/5 + 5/8) + (x/5 - 1/4)
To Find : Sum
Solution:
(2x/5 + 5/8) + (x/5 - 1/4)
= 2x/5 + 5/8 + x5 - 1/4
= 2x/5 + x/5 + 5/8 - 1/4
= (2x + x)/5 + (5 - 2)/8
= 3x/5 + 3/8
= (24x + 15)/40
(2x/5 + 5/8) + (x/5 - 1/4) = 3x/5 + 3/8
or (24x + 15)/40
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1
Answer:
the denominator of rational number is greater than numerator
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